18x^2+39x=15

Solution for 18x^2+39x=15 equation:

18x^2+39x=15

We move all terms to the left:

18x^2+39x-(15)=0

a = 18; b = 39; c = -15;
Δ = b2-4ac
Δ = 392-4·18·(-15)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-51}{2*18}=\frac{-90}{36}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+51}{2*18}=\frac{12}{36}
=1/3
$